|
%I #12 Sep 08 2022 08:45:56
%S 0,0,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,
%T 0,0,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,1,0,0,1,1,
%U 0,0,1,0,0,1,1,0,0,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,1,0,0,1,1,0,0,1,0,0,1,1,0,0,1,0,0,1,0,0,1,1,0,0,1
%N a(n) = [n*r] - [k*r] - [n*r-k*r], where r=1/sqrt(2), k=2, [ ]=floor.
%C See A188014.
%H G. C. Greubel, <a href="/A188297/b188297.txt">Table of n, a(n) for n = 1..10000</a>
%F a(n) = [n*r] - [n*r-2*r] - [2*r], where r=1/sqrt(2).
%t r=2^(-1/2); k=2;
%t t=Table[Floor[n*r]-Floor[n*r-k*r]-Floor[k*r], {n,1,220}] (* A188297 *)
%t Flatten[Position[t,0] ] (* A188298 *)
%t Flatten[Position[t,1] ] (* A188299 *)
%o (PARI) for(n=1,100, print1(floor(n/sqrt(2)) - floor(2/sqrt(2)) - floor((n-2)/sqrt(2)), ", ")) \\ _G. C. Greubel_, Apr 13 2018
%o (Magma) [Floor(n/Sqrt(2)) - Floor(2/Sqrt(2)) - Floor((n-2)/Sqrt(2)): n in [1..100]]; // _G. C. Greubel_, Apr 13 2018
%Y Cf. A188014, A188298, A188299.
%K nonn
%O 1
%A _Clark Kimberling_, Mar 27 2011
|
