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%I #7 Mar 30 2012 18:57:22
%S 0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,
%T 0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,
%U 0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,0,1,0,0,0,1,0
%N [nr+kr]-[nr]-[kr], where r=sqrt(5), k=5, [ ]=floor.
%C See A187950.
%F a(n)=[nr+5r]-[nr]-[5r], where r=sqrt(5).
%t r=5^(1/2); k=5;
%t seqA=Table[Floor[n*r+k*r]-Floor[n*r]-Floor[k*r], {n,1,220}] (* A188291 *)
%t Flatten[Position[seqA,0] ] (* A188292 *)
%t Flatten[Position[seqA,1] ] (* A188293 *)
%Y Cf. A187950, A188292, A188293.
%K nonn
%O 1
%A _Clark Kimberling_, Mar 26 2011