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%I #5 Mar 30 2012 18:57:22
%S 0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,
%T 0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,
%U 0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,0,1,1,0,0,1,1,0,0,1,1
%N [nr+kr]-[nr]-[kr], where r=sqrt(5), k=2, [ ]=floor.
%C See A187950.
%F a(n)=[nr+2r]-[nr]-[2r], where r=sqrt(5).
%t r=5^(1/2); k=2;
%t seqA=Table[Floor[n*r+k*r]-Floor[n*r]-Floor[k*r], {n,1,220}] (* A188257 *)
%t Flatten[Position[seqA,0] ] (* A188258 *)
%t Flatten[Position[seqA,1] ] (* A188259 *)
%Y Cf. A187950, A188258, A188259.
%K nonn
%O 1
%A _Clark Kimberling_, Mar 25 2011
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