|
%I #4 Mar 30 2012 18:57:22
%S 1,1,0,1,1,0,1,0,1,1,0,1,1,1,1,0,1,1,0,1,0,1,1,0,1,1,1,1,0,1,1,0,1,1,
%T 1,1,0,1,1,0,1,0,1,1,0,1,1,1,1,0,1,1,0,1,0,1,1,0,1,1,1,1,0,1,1,0,1,1,
%U 1,1,0,1,1,0,1,0,1,1,0,1,1,1,1,0,1,1,0,1,1,1,1,0,1,1,0,1,0,1,1,0,1,1,1,1,0,1,1,0,1,0,1,1,0,1,1,1,1,0,1,1,0,1,1,1,1,0,1,1,0,1
%N [nr]-[nr-kr]-[kr], where r=(1+sqrt(5))/2, k=6, [ ]=floor.
%C See A188014.
%F a(n)=[nr]-[nr-6r]-[6r], where r=(1+sqrt(5))/2.
%t r=(1+5^(1/2))/2; k=6;
%t t=Table[Floor[n*r]-Floor[(n-k)*r]-Floor[k*r],{n,1,220}] (*A188017*)
%t Flatten[Position[t,0]] (*A188018*)
%t Flatten[Position[t,1]] (*A188019*)
%Y A188014, A188018, A188019.
%K nonn
%O 1
%A _Clark Kimberling_, Mar 19 2011
|
