%I #23 Aug 30 2022 08:12:30
%S 0,0,0,0,1,0,0,0,0,1,0,0,1,0,0,0,0,1,0,0,0,0,1,0,0,1,0,0,0,0,1,0,0,1,
%T 0,0,0,0,1,0,0,0,0,1,0,0,1,0,0,0,0,1,0,0,0,0,1,0,0,1,0,0,0,0,1,0,0,1,
%U 0,0,0,0,1,0,0,0,0,1,0,0,1,0,0,0,0,1,0,0,1,0,0,0,0,1,0,0,0,0,1,0,0,1,0,0,0,0,1,0,0,0,0,1,0,0,1,0,0,0,0,1,0,0,1,0,0,0,0,1,0,0,0,0,1,0,0,1
%N a(n) = [nr] - [nr-kr] - [kr], where r=(1+sqrt(5))/2, k=2, [ ]=floor.
%C See A188014.
%F a(n) = [nr] - [nr-2r] - [2r], where r=(1+sqrt(5))/2.
%F a(n) = A123740(n-2), n >= 3. - _Wolfdieter Lang_, Jun 27 2011
%t r=(1+5^(1/2))/2; k=2;
%t t=Table[Floor[n*r]-Floor[(n-k)*r]-Floor[k*r],{n,1,220}] (* A188009 *)
%t Flatten[Position[t,0]] (* A188010 *)
%t Flatten[Position[t,1]] (* First column of array A101866 *)
%o (Python)
%o from math import isqrt
%o def A188009(n): return (n+isqrt(m:=5*n**2)>>1)-(n-2+isqrt(m-20*(n-1))>>1)-3 if n > 1 else 0 # _Chai Wah Wu_, Aug 29 2022
%Y Cf. A001622, A188014, A188010, A101866, A187950, A123740.
%K nonn
%O 1
%A _Clark Kimberling_, Mar 19 2011