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%I #4 Mar 30 2012 17:25:39
%S 1,2,1,4,3,1,6,5,3,1,9,8,6,3,1,12,11,9,6,3,1,16,15,13,10,6,3,1,20,19,
%T 17,14,10,6,3,1,25,24,22,19,15,10,6,3,1,30,29,27,24,20,15,10,6,3,1,36,
%U 35,33,30,26,21,15,10,6,3,1
%N Triangle by rows, A003983 * A000012 as infinite lower triangular matrices
%C Sum of n-th row terms = A034828(n+1).
%F Given the correlation triangle A003983, partial sums of terms starting from the right.
%e Row 4 = (6, 5, 3, 1), since row 4 of the A003983 triangle = (1, 2, 2, 1).
%e First few rows of the triangle =
%e 1
%e 2, 1
%e 4, 3, 1
%e 6, 5, 3, 1
%e 9, 8, 6, 3, 1
%e 12, 11, 9, 6, 3, 1
%e 16, 15, 13, 10, 6, 3, 1
%e 20, 19, 17, 14, 10, 6, 3, 1
%e 25, 24, 22, 19, 15, 10, 6, 3, 1
%e 30, 29, 27, 24, 20, 15, 10, 6, 3, 1
%e 36, 35, 33, 30, 26, 21, 15, 10, 6, 3, 1
%e 42, 41, 39, 36, 32, 27, 21, 15, 10, 6, 3, 1
%e ...
%Y Cf. A034828
%K nonn,tabl
%O 1,2
%A _Gary W. Adamson_, Mar 15 2011