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%I #5 Dec 04 2016 19:46:24
%S 1,3,5,7,9,11,12,15,16,18,20,22,24,26,28,29,31,34,35,37,39,41,43,45,
%T 46,48,50,52,54,56,58,60,62,63,65,67,69,71,73,75,77,79,80,82,84,86,88,
%U 90,92,94,96,97,99,101,103,105,107,108,111,113,114,116,118,120,122,124,125,127,130,131,133,135,137,139,141,143,145,146,148,150,152
%N Rank transform of the sequence floor(5n/3); complement of A187688.
%C See A187224.
%t seqA = Table[Floor[5n/3], {n, 1, 220}]
%t seqB = Table[n, {n, 1, 220}];(*A000027*)
%t jointRank[{seqA_,
%t seqB_}] := {Flatten@Position[#1, {_, 1}],
%t Flatten@Position[#1, {_, 2}]} &[
%t Sort@Flatten[{{#1, 1} & /@ seqA, {#1, 2} & /@ seqB}, 1]];
%t limseqU =
%t FixedPoint[jointRank[{seqA, #1[[1]]}] &,
%t jointRank[{seqA, seqB}]][[1]] (*A187687*)
%t Complement[Range[Length[seqA]], limseqU] (*A187688*)
%t (*by _Peter J. C. Moses_, Mar 12 2011*)
%Y Cf. A187224, A187688.
%K nonn
%O 1,2
%A _Clark Kimberling_, Mar 12 2011
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