A186672 - OEIS

%I #16 Apr 29 2016 05:15:46

%S 0,6,60,640,6239,60228,600196,6000213,60000231,600000239,6000000240

%N Total number of n-digit numbers requiring 13 positive biquadrates in their representation as sum of biquadrates.

%C A102831(n) + A186650(n) + A186652(n) + A186654(n) + A186656(n) + A186658(n) + A186660(n) + A186662(n) + A186664(n) + A186666(n) + A186668(n) + A186670(n) + a(n) + A186674(n) + A186676(n) + A186678(n) + A186681(n) + A186683(n) + A186685(n) = A052268(n), for n>1.

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/WaringsProblem.html">Waring's Problem.</a>

%F a(n) = A186671(n) - A186671(n-1).

%Y Cf. A046044, A186671.

%K nonn,base,more

%O 1,2

%A _Martin Renner_, Feb 25 2011

%E a(5)-a(11) from _Giovanni Resta_, Apr 29 2016