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%I #11 Nov 14 2024 18:44:12
%S 0,5,34,129,356,805,1590,2849,4744,7461,11210,16225,22764,31109,41566,
%T 54465,70160,89029,111474,137921,168820,204645,245894,293089,346776,
%U 407525,475930,552609,638204,733381,838830,955265,1083424,1224069,1377986,1545985,1728900,1927589,2142934,2375841,2627240
%N a(n) = n*(n^3+n^2+2*n+1).
%C Number of lunar divisors of the number 11111 in base n+1.
%H D. Applegate, M. LeBrun and N. J. A. Sloane, <a href="http://arxiv.org/abs/1107.1130">Dismal Arithmetic</a> [Note: we have now changed the name from "dismal arithmetic" to "lunar arithmetic" - the old name was too depressing]
%t Table[n(n^3+n^2+2n+1),{n,0,40}] (* _Harvey P. Dale_, Nov 14 2024 *)
%K nonn
%O 0,2
%A _N. J. A. Sloane_, Feb 24 2011