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%I #11 Aug 20 2012 11:58:00
%S 1,-1,11,-256,10541,-672136,61001951,-7445096296,1172998147241,
%T -231333927486736,55747918840676411,-16100914826854576456,
%U 5485174647349481371661,-2175023364205612725532456,992565740287786208277022391,-516241740263310751317668520736
%N 2n-th derivative of sech(x)^sech(x) at x=0.
%C sech(x) = 1/cosh(x).
%C The sequence gives only 2n-th derivatives because (2n+1)-th derivatives are 0.
%t f[x_] := Sech[x]^Sech[x]; Table[Derivative[2*n] [f][0],{n,0,18}]
%Y Cf. A186249.
%K sign
%O 0,3
%A _Michel Lagneau_, Aug 18 2012
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