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Indices k for which A185079(k) > k^2.
1

%I #18 Oct 22 2022 14:57:42

%S 18,21,22,24,30,36,40,48,52,56,70,80,82,85,86,90,93,94,100,102,105,

%T 115,116,118,129,132,135,165,177,180,182,183,189,201,203,205,210,213,

%U 214,216,217,224

%N Indices k for which A185079(k) > k^2.

%C For other k >= 2, except for 6, 60, 120, 360, 816, 6120, 8280, ..., we have A185079(k) < k^2. In particular, all terms of the sequence are composite numbers.

%C Conjecture: The sequence is infinite.

%H Amiram Eldar, <a href="/A185099/b185099.txt">Table of n, a(n) for n = 1..3000</a>

%F Limit_{n->oo} a(n)/n^2 = 1.

%Y Cf. A185079.

%K nonn

%O 1,1

%A _Vladimir Shevelev_, Feb 18 2011

%E Corrected by _R. J. Mathar_, Feb 19 2011