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Half the number of (n+1)X4 0..3 arrays with every 2X2 subblock diagonal sum differing from its antidiagonal sum by more than 3
1

%I #5 Mar 31 2012 12:35:58

%S 180,2318,20958,224156,2227254,22904858,231988508,2366228756,

%T 24059229300,244980260166,2492868966664,25374399195344,

%U 258246420327078,2628446232292538,26751738752624652,272276599065597038

%N Half the number of (n+1)X4 0..3 arrays with every 2X2 subblock diagonal sum differing from its antidiagonal sum by more than 3

%C Column 3 of A184231

%H R. H. Hardin, <a href="/A184225/b184225.txt">Table of n, a(n) for n = 1..200</a>

%F Empirical: a(n)=10*a(n-1)+24*a(n-2)-241*a(n-3)+55*a(n-4)+1084*a(n-5)-594*a(n-6)-1710*a(n-7)+1050*a(n-8)+928*a(n-9)-552*a(n-10)-132*a(n-11)+72*a(n-12)

%e Some solutions for 3X4

%e ..3..0..3..2....2..0..3..1....3..0..3..2....1..0..2..1....3..0..3..0

%e ..0..3..0..3....0..3..0..2....1..3..0..3....0..3..0..3....0..2..0..2

%e ..1..0..2..1....2..0..3..0....2..0..2..0....3..0..3..0....3..0..3..1

%K nonn

%O 1,1

%A _R. H. Hardin_ Jan 10 2011