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%I #7 Mar 30 2012 18:57:12
%S 2,5,7,10,12,15,18,20,23,25,28,30,33,36,38,41,43,46,48,51,54,56,59,61,
%T 64,67,69,72,74,77,79,82,85,87,90,92,95,97,100,103,105,108,110,113,
%U 115,118,121,123,126,128,131,134,136,139,141,144,146,149
%N Beatty sequence for (6+sqrt(3))/3.
%C Let u=1+sqrt(3) and v=sqrt(3). Jointly rank {j*u} and {k*v} as in the first comment at A182760; a(n) is the position of n*u.
%F a(n)=floor(n*(6+sqrt(3))/3).
%Y Cf. A182760, A182773.
%K nonn
%O 1,1
%A _Clark Kimberling_, Nov 30 2010