

A180877


Numbers n such that sopfr(n)  (floor(sqrt(n))*bigomega(n)) = floor(sqrt(n)).


0



2, 14, 26, 155, 287, 329, 474, 498, 803, 1079, 1157, 1432, 2786, 3396, 3473, 3611, 5597, 9287, 11357, 12599, 21394, 31418, 49706, 54023, 56978, 61150, 63923, 69791, 72203, 77789, 78431, 80987, 81178, 86897, 99794, 106194, 109994, 110338, 110824
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OFFSET

1,1


LINKS



EXAMPLE

Take the number 287. Find the floor of its square root: sqrt(287)=16.941074... it's 16. Now get the factors of 287 = 7*41. Subtract the first prime factor from the floor of the square root: 716 = 9. Now subtract the second prime factor from the floor of the square root: 4116 = 25. Add those values together: 9+25 = 16. It's the same as the floor of the square root. But it doesn't always work out that way.


CROSSREFS



KEYWORD

nonn


AUTHOR



STATUS

approved



