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%I #3 Mar 31 2012 12:35:46
%S 0,0,0,1,7,57,286,1701,5969,22212,59824,173319,385060,920819,1831674,
%T 3839358,6872225,13243078,21945628,39182616,61892080,103355368,
%U 155139308,251041955,359562489,554717344,780642911,1160794113,1574984248
%N Number of distinct solutions of sum{i=1..5}(x(2i-1)*x(2i)) = 0 (mod n), with x() only in 2..n-2
%C Column 5 of A180823
%H R. H. Hardin, <a href="/A180817/b180817.txt">Table of n, a(n) for n=1..251</a>
%e Solutions for sum of products of 5 2..3 pairs = 0 (mod 5) are
%e (2*2 + 2*2 + 2*2 + 2*2 + 2*2) (2*2 + 2*2 + 2*2 + 2*2 + 3*3)
%e (2*2 + 2*2 + 2*2 + 3*3 + 3*3) (2*2 + 2*2 + 3*3 + 3*3 + 3*3)
%e (2*2 + 3*3 + 3*3 + 3*3 + 3*3) (2*3 + 2*3 + 2*3 + 2*3 + 2*3)
%e (3*3 + 3*3 + 3*3 + 3*3 + 3*3)
%K nonn
%O 1,5
%A _R. H. Hardin_ Sep 20 2010
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