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a(n) = n^5 + 5n.
4

%I #17 Feb 07 2023 08:50:49

%S 0,6,42,258,1044,3150,7806,16842,32808,59094,100050,161106,248892,

%T 371358,537894,759450,1048656,1419942,1889658,2476194,3200100,4084206,

%U 5153742,6436458,7962744,9765750,11881506,14349042,17210508,20511294

%N a(n) = n^5 + 5n.

%H <a href="/index/Rec#order_06">Index entries for linear recurrences with constant coefficients</a>, signature (6,-15,20,-15,6,-1).

%F From _R. J. Mathar_, Sep 24 2010: (Start)

%F G.f.: 6*x*(1+x+16*x^2+x^3+x^4)/(x-1)^6.

%F a(n) = +6*a(n-1) -15*a(n-2) +20*a(n-3) -15*a(n-4) +6*a(n-5) -a(n-6). (End)

%o (PARI) a(n)=n^5+5*n \\ _Charles R Greathouse IV_, Oct 16 2015

%Y Cf. A132411, A079908, A180354.

%K nonn,easy

%O 0,2

%A _Odimar Fabeny_, Aug 30 2010

%E First term corrected by _Odimar Fabeny_, Sep 23 2010

%E a(0) corrected by _R. J. Mathar_, Sep 24 2010