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a(1)=1; a(n)=percentage of sum of previous terms represented by n
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%I #5 Nov 21 2013 12:50:05

%S 100,66,50,40,33,28,25,22,20,18,16,15,14,13,12,11,11,10,10,9,9,8,8,8,

%T 7,7,7,6,6,6,6,6,5,5,5,5,5,5,5,4,4,4,4,4,4,4,4,4,4,3,3,3,3,3,3,3,3,3,

%U 3,3,3,3,3,3,3,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2

%N a(1)=1; a(n)=percentage of sum of previous terms represented by n

%F a(1) = 1

%F a(n) = 100 * n / (n + n-1 + n-2 + ... + 1)

%e a(3)=50 because 1+2+3=6 and 3 is 50% of 6.

%t Floor[200/(Range[90]+1)] (* _Harvey P. Dale_, Jul 24 2011 *)

%K easy,nonn

%O 2,1

%A _Dominick Cancilla_, Aug 09 2010