%I #2 Mar 31 2012 10:25:22
%S 1,3,6,11,20,33,54,87,142,226,360,571,907,1438,2278,3606,5708,9032,
%T 14293,22614,35778,56604,89550,141670,224122,354560,560907,887348,
%U 1403768,2220731,3513149,5557726,8792197,13909055,22003808
%N Sum of previous terms divided by their distance from n
%F a(n) = n + floor(a(n-1)/1) + floor(a(n-2)/2) + ... + floor(a(1)/(n-1))
%e a(1)=1 by definition
%e a(4)=4+a(3)/1+a(2)/2+a(1)/3=4+floor(6/1)+floor(3/2)+floor(1/3)=11
%K nonn
%O 2,2
%A _Dominick Cancilla_, Aug 09 2010