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A178489 a(n) = floor(n^(1/6)): integer part of sixth root of n. 5

%I #12 Dec 22 2016 22:09:21

%S 0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,

%T 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,2,2,2,2,

%U 2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2

%N a(n) = floor(n^(1/6)): integer part of sixth root of n.

%F G.f.: Sum_{k>=1} x^(k^6)/(1 - x). - _Ilya Gutkovskiy_, Dec 22 2016

%t Floor[Power[Range[0,110], (6)^-1]] (* _Harvey P. Dale_, Jul 18 2011 *)

%o (PARI) A178489(n)=floor(sqrtn(n+.5,6))

%o (PARI) a(n) = sqrtnint(n, 6); \\ _Michel Marcus_, Dec 22 2016

%Y Cf. A000196, A048766, A178487.

%K easy,nonn

%O 0,65

%A _M. F. Hasler_, Oct 09 2010

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