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a(n) = A001969(n)^A178253(n).
2

%I #4 Mar 22 2013 14:11:39

%S 81,25,1296,81,100,20736,50625,289,324,400,529,331776,14348907,841,

%T 810000,1089,1156,1296,1521,1600,1849,91125,2116,5308416,2601,7890481,

%U 459165024,601692057,3364,12960000,15752961,4225,4356,4624,5041,5184

%N a(n) = A001969(n)^A178253(n).

%C a(n) is in A000069 for all n.

%C Since A001969(n) = 2*n + A010060(n) it follows that this sequence has the same parity as A010060.

%e A001969(1)=3, A178253(1)=4, a(1)=3^4=81.

%o (PARI) a(n)=my(e=2*n--+hammingweight(n)%2, m=1); e>>=valuation(e, 2); while(hammingweight(e^m++)%2==0, ); e^m \\ _Charles R Greathouse IV_, Mar 22 2013

%Y Cf. A000069, A001969, A010060, A178253.

%K easy,nonn

%O 1,1

%A _Jeremy Gardiner_, May 26 2010