%I #2 Mar 31 2012 13:23:39
%N Multiply the irregular Array A125108 by A178300;compute a(n)the vertical sums.
%C The row sums resulting from the defined multiplication yields A038675.
%C A178301 is a triangular sub-array of A178300 times A125108
%C since A007318 is a sub-array of A125108.
%e A125108(7) = 2 and appears on row five of A125108 so
%e A178300(5) times A125108(7) is 4*2 =8.
%e As a cross-check, note that A178301 = 1,4,19,96,...
%e and with the additional 8 in column 4 we have a(n) = 1,4,19,104,...
%Y Cf. A038675 A125108 A178300 A178301
%A _Alford Arnold_, May 30 2010