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%I #4 Nov 02 2019 14:59:57
%S 1,2,9,6562,12166933384727052833
%N a(1) = 1, for n >= 2: a(n) = a(n-1)^n + 1.
%C a(6) has 115 digits.
%e For n = 4: a(4) = 9^4 + 1 = 6562.
%t RecurrenceTable[{a[1]==1,a[n]==a[n-1]^n+1},a,{n,6}] (* _Harvey P. Dale_, Nov 02 2019 *)
%K nonn
%O 1,2
%A _Jaroslav Krizek_, Nov 03 2010
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