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a(n)=Sum((A008292(n - j, j) - C(n - j - 1, j))/2, j=0, [(n - 1)/2])
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%I #8 Mar 12 2014 16:37:15

%S 0,0,0,0,1,4,15,56,214,854,3607,16172,76853,386082,2044198,11373124,

%T 66300473,403939612,2566116299,16962629860,116452790838,828903740138,

%U 6107712000563,46521422681724,365811331693305,2965957618809246,24767913121016790,212803409969904264

%N a(n)=Sum((A008292(n - j, j) - C(n - j - 1, j))/2, j=0, [(n - 1)/2])

%C Sequence A000800 minus the Lucas Fibonacci sum divided by two.

%D Burton, David M.,Elementary number theory,McGraw Hill,N.Y.,2002,p 286, problem 23

%t a = Table[Sum[(Eulerian[n -

%t j, j] - Binomial[n - j - 1, j])/2, {j, 0,

%t Floor[(n - 1)/2]}], {n, 0, 30}]

%Y Cf. A000800,A000045,A008292

%K nonn

%O 0,6

%A _Roger L. Bagula_, Dec 02 2010