|
%I #3 Jan 20 2014 22:19:35
%S 9,2,45,2,11,2,225,2,11,2,56,2,11,2,1125,2,11,2,56,2,11,281,2,11,2,56,
%T 2,11,2,5625
%N Sequence built as it follows in comments.
%C If we denote "A" the finite sequence between a(2^(n-1)-2) and a(2^n-2), the subsequence of a between
%C a(2^(n)-2) and a(2^(n+1)-2) is given by: " A - a(3*2^(n-1)-2) - A" for every n>=2.
%F a(2n+1)=2. a(2^(n+1)-2)=9*5^n. a(3*2^n-2)=(9*5^n-1)/4.
%e a(4)=a(2*3-2)=(9*4-1)/4=11. a(14)=a(2^4-2)==9*5^3=125*9=1125.
%e Between a(2) and a(6) the subsequence is "2, 11, 2"; then between a(6) and a(14) the subsequence of a is:
%e "2, 11, 2, a(10)=56, 2, 11, 2".
%e It seems that this new sequence gives the number of 2 in the sets of 2 of the sequence A174835.
%Y Cf. A174835.
%K easy,nonn,uned
%O 0,1
%A _Richard Choulet_, Mar 30 2010
|
