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Sequence given by: a(0)=1, a(1)=2, and the formula a(n)=a(abs(floor((1/3)*n-a(n-2)))) for n>=2.
2

%I #4 Jan 20 2014 22:18:26

%S 1,2,2,2,2,2,1,1,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,1,1,1,2,2,1,2,2,2,2,

%T 2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,

%U 2,2,2,2,2,2,2,2,2,2,1,1,1,1,1,1,2,2,1,2,2,2,2,2,2,1,1,2,2,2,2,2,2,2,2,2,2

%N Sequence given by: a(0)=1, a(1)=2, and the formula a(n)=a(abs(floor((1/3)*n-a(n-2)))) for n>=2.

%e a(2)=a(abs(floor(-2/3)))=a(1)=2. a(3)=a(abs(1-a(1)))=a(1)=2. a(4)=a(abs(floor(4/3-2)))=a(1)=2. a(5)=a(abs(floor(5/3-a(3))))=a(1)=2. a(6)=a(2-a(4))=a(0)=1.

%Y Cf. A174353.

%K easy,nonn

%O 0,2

%A _Richard Choulet_, Mar 26 2010