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Irregular triangle, row sums = n.
2

%I #11 Feb 21 2024 08:19:23

%S 1,2,1,2,0,4,2,2,1,4,0,2,2,4,1,0,0,8,0,0,1,4,2,0,2,2,0,4,0,4,1,2,2,0,

%T 2,4,0,4,0,0,0,8,0,2,1,0,4,4,2,0,0,2,0,8,0,4,0,0,1,0,4,8,2,0,0,0,0,0,

%U 0,16,0,0,2,0,0,0,2,8,4,0,1,4,0,0,0,4,0,8,0,2,2,4,0,0,2,4,4,0,1,2,0,8,0,0,0

%N Irregular triangle, row sums = n.

%C Column 1 = A174026.

%C The triangle begins 1, 2,...then all columns >1 are shifted down twice from previous column. Next term in column 1 = n - (sum of terms in n-th row, columns >1). Terms of the triangle for columns >1 are filled in as a product of column 1 * column 1.

%e Triangle begins:

%e 1;

%e 2;

%e 1, 2;

%e 0, 4;

%e 2, 2, 1;

%e 4, 0, 2;

%e 2, 4, 1, 0;

%e 0, 8, 0, 0;

%e 1, 4, 2, 0, 2;

%e 2, 0, 4, 0, 4;

%e 1, 2, 2, 0, 2, 4;

%e 0, 4, 0, 0, 0, 8;

%e 0, 2, 1, 0, 4, 4, 2;

%e 0, 0, 2, 0, 8, 0, 4;

%e 0, 0, 1, 0, 4, 8, 2, 0;

%e 0, 0, 0, 0, 0, 16, 0, 0;

%e 2, 0, 0, 0, 2, 8, 4, 0, 1;

%e 4, 0, 0, 0, 4, 0, 8, 0, 2;

%e 2, 4, 0, 0, 2, 4, 4, 0, 1, 2;

%e 0, 8, 0, 0, 0, 8, 0, 0, 0, 4;

%e ...

%e Example: Leftmost term in column 9 = 1 = (9 - (4 + 2 + 0 + 2)). Then the "1" is entered into the top heading as a multiplier. Multiply, filling in more terms, then obtain next term of left border as before.

%Y Cf. A174026, A174064.

%K nonn,tabf,uned

%O 1,2

%A _Gary W. Adamson_, Mar 06 2010