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%I #2 Mar 30 2012 19:00:22
%S 1,6,36,36864
%N a(1) = 1, for n >= 2; a(n) = the smallest number h such that tau(h) = A000005(h) = a(n-1) + 3.
%C The next term is too large to include.
%F A000005(a(n)) = a(n-1) + 3 for n >= 2.
%Y Cf. A014221, A173603, A173605, A173606, A173607, A173608, A173609, A171959, A173011.
%K nonn
%O 1,2
%A _Jaroslav Krizek_, Nov 06 2010