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a(n) = (3^(3^n) - 1)/2.
1

%I #7 Apr 25 2021 12:21:32

%S 1,13,9841,3812798742493,221713244121518884974124815309574946401

%N a(n) = (3^(3^n) - 1)/2.

%H G. C. Greubel, <a href="/A173506/b173506.txt">Table of n, a(n) for n = 0..6</a>

%F 2*a(n+1) + 1 = ( 2*a(n) + 1 )^3.

%t Table[(3^(3^m) -1)/2, {m, 0, 10}]

%o (Sage) [(3^(3^n) -1)/2 for n in (0..10)] # _G. C. Greubel_, Apr 25 2021

%Y Cf. A051179, A173507.

%K nonn

%O 0,2

%A _Roger L. Bagula_, Feb 20 2010

%E Introduced standard nomenclature in the definition, added recurrence - the Assoc. Editors of the OEIS, Feb 24 2010