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a(n) = - sin^2((2n-1)*arccos(sqrt n)) = sin^2((2n-1)*arcsin(sqrt n)) - 1.
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%I #16 Sep 30 2018 22:39:48

%S -1,0,49,23762,25421763,48225038404,142786923879605,

%T 608447515452613206,3527836867501829594887,26710782540478226038759688,

%U 255922222218837615280903143609,3026917140685147530327256796600410

%N a(n) = - sin^2((2n-1)*arccos(sqrt n)) = sin^2((2n-1)*arcsin(sqrt n)) - 1.

%H Vincenzo Librandi, <a href="/A173171/b173171.txt">Table of n, a(n) for n = 0..170</a>

%t Table[Round[-N[ Sin[(2 n - 1) ArcCos[Sqrt[n]]]^2, 100]], {n, 0, 20}] (* _Artur Jasinski_, Feb 11 2010; Typo fixed by _Vincenzo Librandi_, Jun 29 2014 *)

%Y Cf. A132592, A146311, A146312, A146313, A173115, A173116 A173121, A173127, A173128, A173129, A173130, A173131, A173133, A173134, A173148, A173151, A173170.

%K sign

%O 0,3

%A _Artur Jasinski_, Feb 11 2010