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A product triangle sequence based on recursion:a=4; f(n,a)=(2*a+1)*f(n-1,a)+f(n-2,a)
0

%I #2 Mar 30 2012 17:34:38

%S 1,1,1,1,9,1,1,80,80,1,1,711,6320,711,1,1,6319,499201,499201,6319,1,1,

%T 56160,39430560,350439102,39430560,56160,1,1,499121,3114515040,

%U 246007756722,246007756722,3114515040,499121,1,1,4435929,246007257601

%N A product triangle sequence based on recursion:a=4; f(n,a)=(2*a+1)*f(n-1,a)+f(n-2,a)

%C Row sums are:

%C {1, 2, 11, 162, 7744, 1011042, 429412544, 498245541768, 1880728607247424,

%C 19394268001029953928, 650631110504313946320896,...}.

%C a = 1; A034801.

%C a = 2; A156600.

%C a = 3; A156602.

%C This result seems to connect these new recursions directly to q-forms.

%F a=4; f(n,a)=(2*a+1)*f(n-1,a)+f(n-2,a);

%F c(n)=If[n == 0, 1, Product[f(i, a), {i, 1, n}]];

%F t(n,m)=c(n)/(c(m)*c(n-m)

%e {1},

%e {1, 1},

%e {1, 9, 1},

%e {1, 80, 80, 1},

%e {1, 711, 6320, 711, 1},

%e {1, 6319, 499201, 499201, 6319, 1},

%e {1, 56160, 39430560, 350439102, 39430560, 56160, 1},

%e {1, 499121, 3114515040, 246007756722, 246007756722, 3114515040, 499121, 1},

%e {1, 4435929, 246007257601, 172697094835902, 1534842394188558, 172697094835902, 246007257601, 4435929, 1},

%e {1, 39424240, 19431458835440, 121233114567545603, 9575881454449171680, 9575881454449171680, 121233114567545603, 19431458835440, 39424240, 1},

%e {1, 350382231, 1534839240742160, 85105473729326613333, 59743922859711995180563, 530973050767752120484320, 59743922859711995180563, 85105473729326613333, 1534839240742160, 350382231, 1}

%t Clear[f, c, a, t];

%t f[0, a_] := 0; f[1, a_] := 1;

%t f[n_, a_] := f[n, a] = (2*a + 1)*f[n - 1, a] - f[n - 2, a];

%t c[n_, a_] := If[n == 0, 1, Product[f[i, a], {i, 1, n}]];

%t t[n_, m_, a_] := c[n, a]/(c[m, a]*c[n - m, a]);

%t Table[Flatten[Table[Table[t[n, m, a], {m, 0, n}], {n, 0, 10}]], {a, 1, 10}]

%Y A034801, A156600., A156602.

%K nonn,tabl,uned

%O 0,5

%A _Roger L. Bagula_, Feb 07 2010