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a(1) = 100; for n>1, a(n) = a(n-1) - digitsum(a(n-1)).
2

%I #2 Mar 30 2012 16:51:44

%S 100,99,81,72,63,54,45,36,27,18,9,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

%T 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

%U 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0

%N a(1) = 100; for n>1, a(n) = a(n-1) - digitsum(a(n-1)).

%Y Cf. A169732, A169736.

%K nonn,base

%O 1,1

%A _N. J. A. Sloane_, May 01 2010