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a(n) = n^3*(n^6 + 1)/2.
1

%I #14 Sep 08 2022 08:45:48

%S 0,1,260,9855,131104,976625,5038956,20176975,67109120,193710609,

%T 500000500,1178974511,2579891040,5302250785,10330524764,19221681375,

%U 34359740416,59293940705,99179648100,161343852319,256000004000

%N a(n) = n^3*(n^6 + 1)/2.

%H Vincenzo Librandi, <a href="/A168187/b168187.txt">Table of n, a(n) for n = 0..400</a>

%H <a href="/index/Rec#order_10">Index entries for linear recurrences with constant coefficients</a>, signature (10, -45, 120, -210, 252, -210, 120, -45, 10, -1).

%F a(n) = 10*a(n-1) - 45*a(n-2) + 120*a(n-3) - 210*a(n-4) + 252*a(n-5) - 210*a(n-6) + 120*a(n-7) - 45*a(n-8) + 10*a(n-9) - a(n-10); a(0)=0, a(1)=1, a(2)=260, a(3)=9855, a(4)=131104, a(5)=976625, a(6)= 5038956, a(7)=20176975, a(8)=67109120, a(9)=193710609. - _Harvey P. Dale_, Dec 08 2012

%t Table[n^3(n^6+1)/2,{n,0,20}] (* or *) LinearRecurrence[ {10,-45,120,-210,252,-210,120,-45,10,-1},{0,1,260,9855,131104,976625,5038956,20176975,67109120,193710609},30] (* _Harvey P. Dale_, Dec 08 2012 *)

%o (Magma) [n^3*(n^6+1)/2: n in [0..50]]; // _Vincenzo Librandi_, Apr 25 2011

%K nonn

%O 0,3

%A _N. J. A. Sloane_, Dec 11 2009