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Numbers m = sum_(k=1...n) sigma(k) / k such that sum_(k=1...n) sigma(k) / k is integer for any k.
2

%I #5 Mar 30 2012 19:00:22

%S 1,2,7,9,14,52,149,213,673,1778,3653,6831,9868,570972,2835107,3613594,

%T 47211979,60418265,99909506,1701207282,4587170542,10955668024,

%U 29031152874,114018751785,813149731047

%N Numbers m = sum_(k=1...n) sigma(k) / k such that sum_(k=1...n) sigma(k) / k is integer for any k.

%C Numbers m = A024916(k) / k such that A024916(k) / k is integer for any k. If a(14) exist must be bigger than 82000.

%C Corresponding values of k, and sum_(k=1...n) sigma(k) are given in A056550 and A168133. [From _Jaroslav Krizek_, Nov 21 2009]

%e Number a(3) = 7 is in sequence because A024916(8) / 8 = 56 / 8 = 7 is integer for k = 8.

%K nonn

%O 1,2

%A _Jaroslav Krizek_, Nov 18 2009, Dec 04 2009

%E a(14)-a(25) from _Donovan Johnson_, Jun 16 2011