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a(n) = number of natural numbers m such that n - 9 <= m <= n + 9.
0

%I #12 Jun 29 2023 12:53:57

%S 9,10,11,12,13,14,15,16,17,18,19,19,19,19,19,19,19,19,19,19,19,19,19,

%T 19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,

%U 19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19,19

%N a(n) = number of natural numbers m such that n - 9 <= m <= n + 9.

%C Generalization: If a(n,k) = number of natural numbers m such that n - k <= m <= n + k (k >= 1) then a(n,k) = a(n-1,k) + 1 = n + k for 0 <= n <= k, a(n,k) = a(n-1,k) = 2k + 1 for n >= k + 1 (see, e.g., A158799). a(n) = 9 + n for 0 <= n <= 9, a(n) = 19 for n >= 10.

%H <a href="/index/Rec#order_01">Index entries for linear recurrences with constant coefficients</a>, signature (1).

%F G.f.: (9 - 8*x - x^11)/(1 - x)^2. - _G. C. Greubel_, Jul 12 2016

%t CoefficientList[Series[(9 - 8*x - x^11)/(1 - x)^2, {x, 0, 25}], x] (* _G. C. Greubel_, Jul 12 2016 *)

%K nonn

%O 0,1

%A _Jaroslav Krizek_, Nov 18 2009