%I #6 Aug 10 2015 00:29:17
%S 1,1,1,0,-1,0,1,0,0,-1,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,1,0,0,0,0,1,0,0,
%T 0,0,0,-1,0,0,0,0,0,1,0,0,0,0,0,0,-1
%N Hankel transform of A167750.
%C The nonzero terms appear to be indexed by the quarter-squares floor((n+1)^2/4) = A002620(n+1).
%C abs(a(n)) = A237347(n) - 2. - _Reinhard Zumkeller_, Mar 18 2014
%Y Cf. A167753.
%K sign
%O 0,1
%A _Paul Barry_, Nov 10 2009