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Hankel transform of A167750.
3

%I #6 Aug 10 2015 00:29:17

%S 1,1,1,0,-1,0,1,0,0,-1,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,1,0,0,0,0,1,0,0,

%T 0,0,0,-1,0,0,0,0,0,1,0,0,0,0,0,0,-1

%N Hankel transform of A167750.

%C The nonzero terms appear to be indexed by the quarter-squares floor((n+1)^2/4) = A002620(n+1).

%C abs(a(n)) = A237347(n) - 2. - _Reinhard Zumkeller_, Mar 18 2014

%Y Cf. A167753.

%K sign

%O 0,1

%A _Paul Barry_, Nov 10 2009