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%I #17 Dec 07 2019 12:18:26
%S 0,1,7,9,10,8,11,2,5,3,4,6,12,0,1,7,9,10,8,11,2,5,3,4,6,12,0,1,7,9,10,
%T 8,11,2,5,3,4,6,12,0,1,7,9,10,8,11,2,5,3,4,6,12,0,1,7,9,10,8,11,2,5,3,
%U 4,6,12,0,1,7,9,10,8,11,2,5,3,4,6,12,0,1,7,9,10,8,11,2,5,3,4,6,12,0,1,7,9
%N n^11 mod 13.
%C Equivalently: n^(12*m+11) (mod 13). - _G. C. Greubel_, Jun 17 2016
%H Vincenzo Librandi, <a href="/A167628/b167628.txt">Table of n, a(n) for n = 0..1000</a>
%F a(n+13) = a(n). - _G. C. Greubel_, Jun 17 2016
%t PowerMod[Range[0,100],11,13] (* _Harvey P. Dale_, Oct 31 2011 *)
%o (Sage) [power_mod(n,11,13) for n in range(0, 95)]
%o (PARI) a(n)=n^11%13 \\ _Charles R Greathouse IV_, Apr 06 2016
%K nonn,easy
%O 0,3
%A _Zerinvary Lajos_, Nov 07 2009
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