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a(n) = 3^(2^n) - 2^(2^n).
1

%I #16 Sep 08 2022 08:45:48

%S 1,5,65,6305,42981185,1853015893884545,

%T 3433683820274065740584139537665,

%U 11790184577738583171520532579045597727214748217668409340885505

%N a(n) = 3^(2^n) - 2^(2^n).

%F a(n)= A001047(2^n).

%p A167536 := proc(n) 3^(2^n)-2^(2^n) ; end proc: seq(A167536(n),n=1..10) ; # _R. J. Mathar_, Nov 07 2009

%t a[n_]:= 2^n; Table[3^a[n] - 2^a[n], {n, 0, 10}] (* _G. C. Greubel_, Jun 14 2016 *)

%t Table[3^(2^n) - 2^(2^n), {n, 0, 10}] (* _Vincenzo Librandi_, Jun 15 2016 *)

%o (Magma) [3^(2^n)-2^(2^n): n in [0..10]]; // _Vincenzo Librandi_ Jun 15 2016

%Y Cf. A118004.

%K nonn

%O 0,2

%A _Jamel Ghanouchi_, Nov 06 2009

%E Edited by _R. J. Mathar_, Nov 11 2009

%E Offset changed from 1 to 0 from _Vincenzo Librandi_, Jun 15 2016