login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

a(n) is the smallest positive number B that yields a solution for k = A167219(n).
1

%I #28 Aug 11 2022 03:26:59

%S 3,5,3,10,21,9,17,44,91,7,70,5,186,71,3,377,97,285,760,194,323,1527,

%T 574,1148,3062,25,6133,4603,12276,4605,2499,2187,5182,24563,18426,

%U 7775,49138,12440,9997,98289,36860,73721,196592,82941,393199,294904,786414,49,294907

%N a(n) is the smallest positive number B that yields a solution for k = A167219(n).

%C B is the base in which we can express k as Sum_{i=0..m} B^i * a_i. There is an isomorphism between (Z[B],+) and the positive rationals as the polynomials with integer coefficients considered as a group under addition are isomorphic to the positive rationals considered as a group under multiplication.

%e For k = 21 = 2^0 * 3^1 * 5^0 * 7^1, k = B^0 * 0 + B^1 * 1 + B^2 * 0 + B^3 * 1, so we have to solve the equation 21 = B + B^3 for an integer B. No such B exists.

%e For k = 10 = 2^1 * 3^0 * 5^1, k = B^0 * 1 + B^1 * 0 + B^2 * 1, so we have to solve the equation 10 = 1 + B^2 for an integer B. B = +-3.

%e For k = 12 = 2^2 * 3^1, k = B^0 * 2 + B^1 * 1, so we have to solve the equation 12 = 2 + B for an integer B. B = 10. Are there any numbers other than k=12 for which B = 10 yields a solution?

%o (PARI) lista(nn) = for (k=2, nn, my(f=factor(k), v=primes(primepi(vecmax(f[,1])))); my(p=sum(i=1, #v, 'x^(i-1)*valuation(k,v[i]))); p -= k; my(c=-polcoef(p, 0)); my(q=(p+c)/x); my(d=divisors(c)); for (k=1, #d, if(subst(q, x, d[k]) == c/d[k], print1(d[k], ", ")););); \\ _Michel Marcus_, Aug 09 2022

%Y Cf. A054841, A054842, A167219.

%K nonn

%O 1,1

%A _Ctibor O. Zizka_, Oct 30 2009

%E Edited by _Jon E. Schoenfield_, Mar 16 2022

%E Corrected and extended by _Michel Marcus_, Aug 09 2022

%E a(41) and beyond from _Michael S. Branicky_, Aug 10 2022