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A166384
a(n) = (5*n)!/(2*n)!.
1
1, 60, 151200, 1816214400, 60339831552000, 4274473667143680000, 553761949463615692800000, 118528911546113729396736000000, 38996486014317601426443730944000000
OFFSET
0,2
COMMENTS
Integral representation as n-th moment of a positive function on a positive halfaxis (solution of the Stieltjes moment problem), in Maple notation:
a(n) = int(x^n*((1/3125)*sqrt(5)*((625/4)*Pi*csc((2/5)*Pi)*csc((1/5)*Pi)*sin((3/10)*Pi)*GAMMA(7/10)*2^(2/5)*hypergeom([7/10], [2/5, 3/5, 4/5], -(4/3125)*x)/(GAMMA(4/5)*x^(4/5)) - (625/4)*Pi*sec((3/10)*Pi) *csc((2/5)*Pi)*sin((1/10)*Pi)*GAMMA(9/10)*2^(4/5)*hypergeom([9/10], [3/5, 4/5, 6/5], -(4/3125)*x)/(GAMMA(3/5)*x^(3/5)) - (125/8)*Pi*sec((3/10)*Pi)*GAMMA(3/5)*2^(1/5)*hypergeom([11/10], [4/5, 6/5, 7/5], -(4/3125)*x)/(GAMMA(9/10)*x^(2/5)) + (125/8)*Pi*csc((2/5)*Pi)*GAMMA(4/5)*2^(3/5)*hypergeom([13/10], [6/5, 7/5,8/5], -(4/3125)*x)/(GAMMA(7/10)*x^(1/5)))/Pi^(3/2)), x=0..infinity),n=0,1... .
This solution is not unique.
From G. C. Greubel, May 12 2016: (Start)
2^n * 10^(floor[n/2]) | a(n), for n>=0.
2^(2*n) * 10^(floor[n/2]) | a(n), for n>=2. (End)
LINKS
FORMULA
G.f.: sum(a(n)*x^n/((n!)^4),n=0..infinity) = hypergeom([1/5, 2/5, 3/5, 4/5],[1/2, 1, 1, 1], (3125/4)*x).
asymptotics: a(n) = sqrt(10)*(1/2-1/(80*n)+1/(6400*n^2)+(619/3840000)*sqrt(2)/n^3+O(1/n^4))*(5^n)^5/(((1/n)^n)^3*(exp(n))^3*(2^n)^2),n->infinity.
MATHEMATICA
Table[ (5*n)!/(2*n)!, {n, 0, 25}](* G. C. Greubel, May 12 2016 *)
CROSSREFS
Sequence in context: A123378 A221692 A265714 * A180261 A348819 A259540
KEYWORD
nonn
AUTHOR
Karol A. Penson, Oct 13 2009
STATUS
approved