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Inverse permutation to A162501.
4

%I #7 Mar 18 2022 21:52:25

%S 1,5,9,13,17,21,25,29,33,2,3,4,8,12,16,20,24,28,32,6,7,39,40,42,44,46,

%T 48,50,52,10,11,41,57,58,60,62,64,66,68,14,15,43,59,73,74,76,78,80,82,

%U 18,19,45,61,75,87,88,90,92,94,22,23,47,63,77,89,99,100,102,104,26,27

%N Inverse permutation to A162501.

%C A162501(a(n)) = a(A162501(n)) = n.

%C a(a(n)) = A162504(n).

%H R. Zumkeller, <a href="/A162502/b162502.txt">Table of n, a(n) for n = 1..1000</a>

%H <a href="/index/Per#IntegerPermutation">Index entries for sequences that are permutations of the natural numbers</a>

%K nonn

%O 1,2

%A _Reinhard Zumkeller_, Jul 05 2009