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a(n) = n - reversal(n-1).
1

%I #9 Dec 25 2025 18:46:19

%S 1,1,1,1,1,1,1,1,1,1,10,1,-8,-17,-26,-35,-44,-53,-62,-71,19,10,1,-8,

%T -17,-26,-35,-44,-53,-62,28,19,10,1,-8,-17,-26,-35,-44,-53,37,28,19,

%U 10,1,-8,-17,-26,-35,-44,46,37,28,19,10,1,-8,-17,-26,-35,55,46,37,28,19,10,1,-8

%N a(n) = n - reversal(n-1).

%C a(8)=8-R(7)=8-7=1; a(15)=15-R(14)=15-41=-26; a(26)=26-R(25)=26-52=-26

%H Harvey P. Dale, <a href="/A160928/b160928.txt">Table of n, a(n) for n = 1..1000</a>

%t Table[n-IntegerReverse[n-1],{n,70}] (* _Harvey P. Dale_, Dec 25 2025 *)

%K base,sign

%O 1,11

%A _Claudio Meller_, May 30 2009