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%I #13 Aug 28 2018 13:57:06
%S 2,3,2,3,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,3,2,2,2,2,2,2,2,2,2,3,
%T 2,2,3,2,2,2,3,2,2,3,3,2,3,2,4,4,2,2,2,2,2,2,3,2,2,3,2,2,3,3,2,2,2,2,
%U 2,3,3,2,3,2,2,3,2,3,3,2,2,2,3,2,2,3,2,2,2,5,2,2,2,2,2,2,2,4,2
%N Integral quotients occur consecutively this many times (in sequence associated with A051838 and A116536).
%e a(1)=2 because the 1st subsequence (38,39) of consecutive integers has run length 2.
%e a(2)=3 because the 2nd subsequence is (56,57,58) which has run length 3.
%e a(3)=2 because the 3rd subsequence is (167,168) which has run length 2.
%Y Cf. A051838, A116536, A140763, A159578, A159581.
%K easy,nonn
%O 1,1
%A _Enoch Haga_, Apr 16 2009
%E Recomputed based on b-file of A051838. - _R. J. Mathar_, Aug 28 2018