%I #2 Mar 30 2012 17:37:48
%S 1,54,62,4190,4920,10538,12376,16065,16732,26345,37236,47026,48323,
%T 53480,56712,58520,61209,62337,65163,83720,84135,94520,100980,126238,
%U 135266,141078,143726,146910,147354,154238,174217,183505,185334,207328
%N Numbers n such that product of double factorials of the digits of n equals sigma(n).
%e sigma(444119)=4!!*4!!*4!!*1!!*1!!*9!!, so 444119 is in the sequence.
%t Select[Range[210000],DivisorSigma[1,# ]==Apply[Times,IntegerDigits[ # ]!! ]&]
%Y Cf. A137603, A158990, A158991, A158992.
%K base,easy,nonn
%O 1,2
%A _Farideh Firoozbakht_, Jul 07 2009