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A158973 a(n) = count of numbers k <= n such that all proper divisors of k are divisors of n. 3

%I #19 Sep 08 2022 08:45:43

%S 1,2,3,4,4,6,5,7,6,7,6,11,7,9,9,10,8,12,9,13,11,11,10,17,11,12,12,14,

%T 11,18,12,16,14,14,14,20,13,15,15,20,14,20,15,19,20,17,16,25,17,20,18,

%U 20,17,23,19,24,19,19,18,29,19,21,24,24,21,25,20,24,22,27,21,32,22,24,26

%N a(n) = count of numbers k <= n such that all proper divisors of k are divisors of n.

%C For primes p, a(p) = A036234(p) = A000720(p) + 1.

%H Robert Israel, <a href="/A158973/b158973.txt">Table of n, a(n) for n = 1..10000</a>

%F a(n) = A000005(n) + A004788(n-1). - _Vladeta Jovovic_, Apr 07 2009 (Corrected by _Altug Alkan_, Nov 25 2015)

%e For n = 8 we have the following proper divisors for k <= n: {1}, {1}, {1}, {1, 2}, {1}, {1, 2, 3}, {1}, {1, 2, 4}. Only k = 6 has a proper divisor that is not a divisor of 8, viz. 3. Hence a(8) = 7.

%p N:= 1000: # to get a(1) to a(N)

%p A:= Vector(N, numtheory:-tau):

%p for p in select(isprime,[2,seq(i,i=3..N,2)]) do

%p for d from 0 to floor(log[p](N))-1 do

%p R:= [seq(seq(p^d*(i+p*j), j=1..floor((N/p^d - i)/p)), i=1..p-1)];

%p A[R]:= map(`+`,A[R],1);

%p od

%p od:

%p convert(A,list); # _Robert Israel_, Nov 24 2015

%t f[n_] := Block[{d = Most@ Divisors@ n}, Select[Range@ n, Union[Most@ Divisors@ #, d] == d &]]; Array[Length@ f@ # &, {75}] (* _Michael De Vlieger_, Nov 25 2015 *)

%o (Magma) [ #[ k: k in [1..n] | forall(t){ d: d in Divisors(k) | d eq k or d in Divisors(n) } ]: n in [1..75] ];

%o (PARI) a004788(n) = {sfp = Set(); for (k=1, n-1, sfp = setunion(sfp, Set(factor(binomial(n, k))[, 1]))); return (length(sfp));}

%o a(n) = numdiv(n) + a004788(n-1); \\ _Altug Alkan_, Nov 25 2015

%Y Cf. A000040, A000720, A036234.

%K nonn

%O 1,2

%A _Jaroslav Krizek_, Apr 01 2009

%E Edited and extended by _Klaus Brockhaus_, Apr 06 2009

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Last modified March 28 04:13 EDT 2024. Contains 371235 sequences. (Running on oeis4.)