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%I #11 Sep 08 2016 04:25:00
%S 2,3,1,5,2,7,1,3,3,11,2,13,3,3,1,17,2,19,2,4,4,23,2,4,5,3,3,29,3,31,1,
%T 5,5,5,2,37,6,6,2,41,3,43,3,3,6,47,2,7,3,7,3,53,2,7,2,7,7,59,2,61,7,3,
%U 1,8,4,67,4,8,4,71,2,73,8,4,4,8,4,79,2,3,9,83,3,9,9,9,3,89,3,9,4,9,9,9,2,97
%N Erroneous version of A079866.
%C We do not begin with the unit 1 because it has no prime factors. Conjecture: The sequence contains the set of prime numbers more than once.
%F The geometric mean is the n-th root of the product of n numbers.
%F Gm = (a(1)*a(2)*...*a(n))^(1/n).
%e 12=2*2*3 has 3 factors; 12^(1/3) = 2.289428... so 2 is in the 11th position in the sequence.
%o (PARI) g(n) = for(x=2,n,print1(floor(x^(1/bigomega(x)))","))
%K dead
%O 2,1
%A _Cino Hilliard_, Mar 21 2009
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