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a(n)=binomial((n+1)^3,n+2), n=1,2... .
2

%I #10 Aug 17 2013 22:14:05

%S 56,17550,7624512,4690625500,3945414736440,4376415781435698,

%T 6208116950265950720,10979605475032835080440,

%U 23706860441577319154916000,61404775345409777291865554700,187991090980490068224949481365440

%N a(n)=binomial((n+1)^3,n+2), n=1,2... .

%C a(0) would be 0. - _Michel Marcus_, Aug 17 2013

%H Vincenzo Librandi, <a href="/A158362/b158362.txt">Table of n, a(n) for n = 1..200</a>

%t Table[(Binomial[(n + 1)^3, n + 2]), {n, 1, 20}] (* _Vincenzo Librandi_, Aug 17 2013 *)

%o (PARI) a(n) = binomial((n+1)^3,n+2); \\ _Michel Marcus_, Aug 17 2013

%K nonn

%O 1,1

%A _Karol A. Penson_, Mar 17 2009