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%I #9 Jun 24 2022 23:37:40
%S 1,5,7,9,10,14,15,19,21,23,25,29,30,32,34,36,37,41,43,45,47,49,50,54,
%T 55,59,61,63,64,68,69,71,73,75,77,81,82,86,88,90,91,95,96,100,102,104,
%U 106,108,109,113,114,116,118,122,123,127,129,131,132,136,137,141,143,145
%N a(n)=S(S(n)) where S=A054353 gives the partial sums of Kolakoski sequence.
%F a(n) = Sum_{k=1..n} (1/2)*(3+(-1)^k)*A000002(k) = (3/2)*A054353(n)+(1/2)*A074272(n).
%Y Cf. A000002, A054353, A074272.
%Y Partial sums of A088570.
%K nonn
%O 1,2
%A _Benoit Cloitre_, Mar 15 2009