OFFSET
1,1
COMMENTS
The identity (10368*n^2-15840*n+6049)^2-(36*n^2-55*n+21)*(1728*n-1320)^2=1 can be written as a(n)^2-A157262(n)*A157263(n)^2=1. - Vincenzo Librandi, Jan 27 2012
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 1..10000
Vincenzo Librandi, X^2-AY^2=1
Index entries for linear recurrences with constant coefficients, signature (3,-3,1).
FORMULA
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3). - Vincenzo Librandi, Jan 27 2012
G.f.: x*(-577-14110*x-6049*x^2)/(x-1)^3. - Vincenzo Librandi, Jan 27 2012
E.g.f.: (10368*x^2 - 5472*x + 6049)*exp(x) - 6049. - G. C. Greubel, Feb 04 2018
MATHEMATICA
LinearRecurrence[{3, -3, 1}, {577, 15841, 51841}, 40] (* Vincenzo Librandi, Jan 27 2012 *)
Table[10368n^2-15840n+6049, {n, 30}] (* Harvey P. Dale, Nov 18 2024 *)
PROG
(Magma) I:=[577, 15841, 51841]; [n le 3 select I[n] else 3*Self(n-1)-3*Self(n-2)+1*Self(n-3): n in [1..40]]; // Vincenzo Librandi, Jan 27 2012
(PARI) for(n=1, 40, print1(10368*n^2 - 15840*n + 6049", ")); \\ Vincenzo Librandi, Jan 27 2012
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Vincenzo Librandi, Feb 26 2009
STATUS
approved
