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Least k such that 2^(2^k) = n (mod k).
1

%I #16 Mar 18 2024 16:05:48

%S 1,3,14,11,6,1941491,10,83,31,13,123,35,71,27,34913,241,18,8059,34,

%T 349,44,25,39,100867561,76,231,253,66203,57,227,139,45,184,37,111,97,

%U 55,41,103,1099,81,66791,53

%N Least k such that 2^(2^k) = n (mod k).

%C First occurrence of n in sequence A155836.

%C a(43) > 12500000. - _Tyler Busby_, Mar 15 2024

%Y Cf. A015910 (2^n mod n), A036236, A155836.

%K nonn,more

%O 0,2

%A _T. D. Noe_, Jan 29 2009