login
a(n) = 11^n - 4^n + 1^n.
18

%I #27 Jul 27 2024 09:38:56

%S 1,8,106,1268,14386,160028,1767466,19470788,214293346,2357685548,

%T 25936376026,285307476308,3138411599506,34522645035068,

%U 379749565147786,4177247095673828,45949725568604866,505447011319424588,5559917244772754746,61159090173536639348,672749993833048381426

%N a(n) = 11^n - 4^n + 1^n.

%H Paolo Xausa, <a href="/A155632/b155632.txt">Table of n, a(n) for n = 0..950</a>

%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (16,-59,44).

%F G.f.: 1/(1-11*x)-1/(1-4*x)+1/(1-x).

%F E.g.f.: e^(11*x)-e^(4*x)+e^x.

%F a(n) = 15*a(n-1)-44*a(n-2)+30 with a(0) = 1, a(1) = 8. - _Vincenzo Librandi_, Jul 21 2010

%t Table[11^n - 4^n + 1, {n, 0, 25}] (* _Paolo Xausa_, Jul 26 2024 *)

%o (PARI) a(n)=11^n-4^n+1 \\ _Charles R Greathouse IV_, Sep 24 2015

%Y Cf. A155596, A155597, A155598, A155599, A155600, A155601, A155622, A155623, A155624, A155625, A155626, A155627, A155628, A155629, A155630, A155631.

%K nonn,easy

%O 0,2

%A _Mohammad K. Azarian_, Jan 30 2009